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y′′−3y′+2y=x2 up vote 3 down vote favorite Solve y′′−3y′+2y=x2
My approach:
Homogen solution:
y=Aex+Be2xParticular solution:
yp=x(Ax2+Bx+C)=Ax3+Bx2+Cx y′p=3Ax2+2Bx+C y′′p=6Ax+2BPut his into the initial equartion to get A, B and C gives me: A=0,B=1/2,C=3/2
This leads me to the answer:
y=Aex+Be2x+x2/2+3x/2However the correct answer is
y=Aex+Be2x+x2/2+3x/2+7/4Where's my miss? Where comes the last term from?
4 года назад
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